3p^2-12p-26=-9

Solution for 3p^2-12p-26=-9 equation:

3p^2-12p-26=-9

We move all terms to the left:

3p^2-12p-26-(-9)=0

We add all the numbers together, and all the variables

3p^2-12p-17=0

a = 3; b = -12; c = -17;
Δ = b2-4ac
Δ = -122-4·3·(-17)
Δ = 348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{348}=\sqrt{4*87}=\sqrt{4}*\sqrt{87}=2\sqrt{87}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{87}}{2*3}=\frac{12-2\sqrt{87}}{6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{87}}{2*3}=\frac{12+2\sqrt{87}}{6}
$